Question

Find the quadratic polynomial whose zeores are 21/8 and 5/16

Answer 1

Step-by-step explanation:

Hey there !

The zeroes be α and ß

Sum of zeroes = α + β =  21/8

Product of zeroes = αβ =  5/16

The required quadratic polynomial is

 k {x² - (α+ß)x + aß}

 k {x² - (21/8)x+5/16}

 k {x²-42x/16 + 5/16}

here , 

 k = 16

16{x²-42x/16 + 5/16}

 16x² - 42x + 5                  -

Answer 2

Step-by-step explanation:

Alpha = 21/8, beta = 5/16

quadratic equation = k[x² - (alpha + beta)x + alpha × beta ]

= k[x² - (21/8 + 5/16)x + 21/8 × 5/16].

= k[x² - 47/16x + 105/128.]

taking k = 1...

quadratic equation = x² - 47/16x + 105/128......

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