Question

Find the quadratic polynomial whose zero are 3+2 root 2 and 3minus 2 root 2​

Answer 1

Step-by-step explanation:

$x = 3 + 2 \sqrt{2} \\ x - 3 - 2 \sqrt{2} = 0 \\ \\ x = 3 - 2 \sqrt{2} \\ x - 3 + 2 \sqrt{2} = 0 \\ multiply \: both \\ (x - 3 - 2 \sqrt{2} )(x - 3 + 2 \sqrt{2} ) = 0 \\ {(x - 3)}^{2} - {(2 \sqrt{2} )}^{2} = 0 \\ {x}^{2} - 6x + 9 - 8 = 0 \\ {x}^{2} - 6x + 1 = 0$

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