Math, asked by vpbhaktha2006, 10 months ago

find the quadratic polynomial whose zeroes are -2√3 and -√3÷2​

Answers

Answered by vsmuthe1970
2

Answer:

2x² + 5√3x + 6 = 0

Step-by-step explanation:

Let both the zeros be α and β respectively.

i.e α = -2√3 ;  β = -√3÷2

As we know that,

x² - (α+β)x + α×β = 0

x² - (-2√3 + [-√3/2])x + [2√3 × √3/2] = 0

x² +√3 ( 4+1/2 )x  +  3 = 0

2x² + 5√3x + 6 = 0

The above equation is the required quadratic equation.

I hope you understood the procedure.

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