find the quadratic polynomial whose zeroes are -2√3 and -√3÷2
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Answer:
2x² + 5√3x + 6 = 0
Step-by-step explanation:
Let both the zeros be α and β respectively.
i.e α = -2√3 ; β = -√3÷2
As we know that,
x² - (α+β)x + α×β = 0
x² - (-2√3 + [-√3/2])x + [2√3 × √3/2] = 0
x² +√3 ( 4+1/2 )x + 3 = 0
2x² + 5√3x + 6 = 0
The above equation is the required quadratic equation.
I hope you understood the procedure.
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