Question

Find the quadratic polynomial whose zeroes are √2+3 and root2-3​

Answer 1

Answer:

2+9+6√2 and √3-3+887fgg

Answer 2

Step-by-step explanation:

sum of the zeros =

$\sqrt{2 } + 3 + \sqrt{2} - 3 = 2 \sqrt{2}$

product of zeros =

$( \sqrt{2} + 3)( \sqrt{2} - 3) = { \sqrt{2} }^{2} - {3}^{2} = 2 - 9 = - 7$

polynomial is

${x}^{2} - (sum \: of \: \\ zeros)x + (product \: of \: zeros)$

${x}^{2} - 2 \sqrt{2} x - 7$