Find the quadratic polynomial whose zeroes are -2& 3
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Let -2& 3 are the zeroes of polynomial p(x)=0 that is ax^2 +bx+ c=0
sum of zeroes =
-( coefficient of x)/(coefficient of x^2)
-2 +3 =-b/a
1/1 = -b/a
product of zeroes =
(constant term)/(coefficient of x^2)
-2×3=c/a
-6/a= c/a
Therefore a=1 , b= -1, c= -6
Hence the quadratic polynomial is x^2 -x -6.
sum of zeroes =
-( coefficient of x)/(coefficient of x^2)
-2 +3 =-b/a
1/1 = -b/a
product of zeroes =
(constant term)/(coefficient of x^2)
-2×3=c/a
-6/a= c/a
Therefore a=1 , b= -1, c= -6
Hence the quadratic polynomial is x^2 -x -6.
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