find the quadratic polynomial whose zeroes are 2 and 1/3
Answers
Answered by
0
Answer:
3x²-7x+2=0
Step-by-step explanation:
let roots of eqⁿ be a,b
We know that,x²-(a+b)x+ab
=x²-(7/3)x+2/3=0
Multiply the eqⁿ by 3
3x²-7x+2=0 is the required polynomial
Similar questions