find the quadratic polynomial whose zeroes are 2 and 1/3
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Step-by-step explanation:
to make quadratic polynomial :- K[x^2- ( sum of zeroes)x + product of zeroes ].
two zeroes are given which is 2 and 1/3
now
to make quadratic polynomial we need to find sum of zeroes and product of it .
so, sum of square is = - b /a = 2+ 1/3 = -7/3
product = c/a = 2× 1/3 = 2/3
to make quadratic polynomial
K[ x^2 -(-7/3)x + 2/3 ].
K [ x^2 + 7/3x + 2/3 ].
now to remove denominator 3. we will take K as 3.
then ,
3x^2 + 7x + 2
hence it a quadratic polynomial.
I hope you have understood.
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