Question

find the quadratic polynomial whose zeroes are 3-2 root 5 and 3+2 root 5...

whoever will help me with this I'll mark him/her as the brainliest​

Answer 1

Answer:

Given:-

• Zeroes of quadratic polynomial are 3 -2√5 and 3 + 2√5.

To Find:-

• Quadratic Polynomial

Solution:-

Let ,

• Alpha = 3 - 2√5

• Beta = 3 + 2√5

Sum of zeroes = 3 - 2√5 + 3 +2√5

=> 3 + 3

=> 6

Product of zeroes = ( 3 - 2√5) ( 3 + 2√5)

=> 3² - (2√5)²

=> 9 - 20

=> -11

Therefore,

Required Quadratic polynomial = x² - ( Sum of zeroes)x + Product of zeroes

=> x² - ( 6 )x + ( -11 )

=> x² - 6x - 11

Hence, the required quadratic polynomial is x² - 6x - 11.

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Answer 2

Answer:

Let the natural number be x² and its square

root be x.

Then, we have

x² + x = 132

x² + x - 132 = 0

x² + 12x - 11x -132 = 0

x (x + 12) - 11 (x +12) = 0

(x+12) (x - 11) = 0

x = -12 and 11