Find the quadratic polynomial whose zeroes are 3+√5 and 3-√5?
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Answer:
Step-by-step explanation:
zeroes = 3+root5 and 3-root5
product of zeroes= (3+root5)(3-root5)
= 9-5
=4
sum of zeroes=3+root5 + 3-root5
=6
we know p(x) = k(x2^ - sum of zeroes (x) + product of zeroes
= k(x2^ -6x +4)
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