Question

find the quadratic polynomial whose zeroes are 3+√5 and 3-√5

Answer 1

hey dude ....
hre is ur answer....!!!

Given ->
3 - √5 and 3 + √5 are zeros of a polynomial

let p(x) be required polynomial
====> x - (3 + √5) and x - (3 - √5) are factors of p(x)

====> [x - (3 + √5)] [x - (3 - √5) is required polynomial

= [x - 3 - √5] [x - 3 + √5]

= x - 3x + √5x - 3x + 9 - 3 √5 - √5x +
3 √5 - 5

= x² - 6x + 4

or...


zeroes = 3+root5 and 3-root5
product of zeroes= (3+root5)(3-root5)
= 9-5
=4
sum of zeroes=3+root5 + 3-root5
=6
we know p(x) = k(x2^ - sum of zeroes (x) + product of zeroes
= k(x2^ -6x +4)

hope it will.help u..


thanks. !

Answer 2

Answer:

Step-by-step explanation: