Question

find the quadratic polynomial whose zeroes are 3/5and-1/2​

Answer 1

$10 {x}^{2} - x - 3$

Step-by-step explanation:

$= {x}^{2} - ( \frac{3}{5} - \frac{1}{2} )x + \frac{3}{5} \times ( \frac{ - 1}{2} ) \\ solving \: this \: we \: get \: q needed \: quadratic \: equation$

Answer 2

Given:
———-

Alpha = 3/5

Beta = -1/2

Relation between zeroes and coefficients of Quadratic polynomial equation can be written as:

X^2 - (alpha + beta)X + (alpha*beta) = 0

X^2 - ((3/5) + (-1/2))X + (3/5)(-1/2) = 0

X^2 - ((6-5)/10)X + (-3/10) = 0

X^2 - (1/10)X - (3/10) = 0

10 X^2 - X - 3 = 0

Answer: 10 X^2 - X - 3 = 0