Question

Find the quadratic polynomial whose zeroes are √3 and -√3

Answer 1

Answer:

(x=√3) (x=-√3)

(x-√3)(x+√3)=x^2+x√3-x√3-3

=x^2-3

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Answer 2

Answer:

Step-by-step explanation:

Sum of zeroes = α + β = $\sqrt{3}$ - $\sqrt{3}$ = 0

Product of zeroes = αβ = $\sqrt{3}$/-$\sqrt{3}$ = -1

∴ p(x) = x² -(α+β) + αβ

   = x²-1