find the quadratic polynomial whose zeroes are √3+√ and √3-√5
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Answer :
- Hence the quadratic polynomial eqution formed is.
x2-√6x-16 .
Given:
- the guadratic polynomial eqution whose roots are
x = ✓3+✓5 ,✓3-✓5 [p(x)=0]
required explanation :
- quadratic polynomial eqution formula:
X2 -(a+B )+a.B= 0
Solution:
- from used the quadratic polynomial eqution formula and value use in ,we get.
p(x) =
a = ✓3-✓5 | B = ✓3+✓5 [put them]
X2-(a+B)x+(a-B)=0
=> X2-(✓3-✓5+✓3-✓5)x+(✓3-✓5×✓3+✓5)=0
[a2-b2=(a-b) (a+b)]
=> X2-√6x+9-25=0
=> x2-√6x-16=0
Similarly quadratic polynomial eqution whose find roots value .√3-√5 , √3+√5 put
answer....
....x2 -√6x-16= 0
if you don't mind checked answer....
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