Question

Find the quadratic polynomial whose zeroes are -3 and 4​

Answer 1

Hiii.....friend,

Here is ur answer,

$= > {x}^{2} - (sum \: of \: zeroes)x + product \: of \: zeroes \: = 0$

$= > {x}^{2} - (4 - 3)x + 4( - 3) = 0$

$= > {x}^{2} - x - 12 = 0$

:-) Hope it helps u.

Answer 2

Answer:

Given zeros are

α

=

2

and

β

=

−

6

.

⇒

Sum of zeros

=

α

+

β

=

2

+

(

−

6

)

=

−

4

⇒

Product of zeros

=

α

×

β

=

2

×

(

−

6

)

=

−

12

⇒

Quadratic polynomial

=

x

2

−

(

α

+

β

)

x

+

(

α

×

β

)

⇒

Quadratic polynomial

=

x

2

−

(

−

4

)

x

+

(

−

12

)

∴

Quadratic polynomial

=

x

2

+

4

x

−

12

Step-by-step explanation:

now you got the answer now please mark brainliesr