Question

find the quadratic polynomial whose zeroes are -3 and 4​

Answer 1

$\large\bf\underline\red{Answer \: :-}$

How to solve

When we ask like this question then, we know that any quadratic zeros made like (x-1) = 0 , x = 1 . Also here we write in that type and multiply both bracket and which equation we that is our Quadratic equation.

We can write,

$\sf\implies{(x + 3)(x - 4) = 0} \: \: \: \: \: \: \: \: \: \: \\ \sf\implies{x(x - 4) + 3(x - 4) = 0} \\ \sf\implies{x {}^{2} - 4x + 3x - 12 = 0 } \: \: \: \\ \sf\implies \purple{x {}^{2} - x - 12 = 0 } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \:$

Quadratic equation : x² - x - 12 = 0

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