find the quadratic polynomial whose zeroes are 3 and 5
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Answer:
x² + 2x - 15
Step-by-step explanation:
Let one zero (3) be α
Let other zero (- 5) be β
Sum of zeros = α + β = ( 3 + { - 5 } ) = - 2
Product of zeros = αβ = { 3 x - 5 } = - 15
We know that,
p(x) = x² - ( α + β )x + αβ
p(x) = x² - ( - 2 )x + ( - 15 )
p(x) = Let one zero (3) be α
Let other zero (- 5) be β
Sum of zeros = α + β = ( 3 + { - 5 } ) = - 2
Product of zeros = αβ = { 3 x - 5 } = - 15
We know that,
p(x) = x² - ( α + β )x + αβ
p(x) = x² - ( - 2 )x + ( - 15 )
p(x) = x² + 2x - 15
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