Find the quadratic polynomial whose zeroes are 3+root5 and 3-root5
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Answered by
76
Hii friend,
(3+✓5) and (3-✓5) are the zero of the polynomial.
Let alpha = 3+✓5 and Beta = 3-✓5.
Sum of zeros = (Alpha + Beta) = (3+✓5) + (3-✓5) = 6
Product of zeros = (Alpha × Beta) = (3+✓5)(3-✓5) = (3)² - (✓5)² = 9-5 = 4.
Therefore,
QUADRATIC POLYNOMIAL = X²-(Alpha + Beta)X + Alpha × Beta
=> X²-6X+4
Hence,
The Quadratic polynomial = X²-6X+4.
HOPE IT WILL HELP YOU..... :-)
(3+✓5) and (3-✓5) are the zero of the polynomial.
Let alpha = 3+✓5 and Beta = 3-✓5.
Sum of zeros = (Alpha + Beta) = (3+✓5) + (3-✓5) = 6
Product of zeros = (Alpha × Beta) = (3+✓5)(3-✓5) = (3)² - (✓5)² = 9-5 = 4.
Therefore,
QUADRATIC POLYNOMIAL = X²-(Alpha + Beta)X + Alpha × Beta
=> X²-6X+4
Hence,
The Quadratic polynomial = X²-6X+4.
HOPE IT WILL HELP YOU..... :-)
Answered by
52
hey friend here is your answer
plz see this attachment
hope this will help u...
Attachments:
01RoyalRajput:
payal ek aur
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