Find the quadratic polynomial whose zeroes are -3and 2
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Answered by
3
Answer:
x square+x-6
Step-by-step explanation:
k=[x square-x(alpa+beta)+alpa*beta]
k=[x square-x(-3+2)+(-3)*2]
k=[x square+x-6]
=[x square+x-6]
Answered by
5
zeroes = -3, 2 alpha = -3 , beta = 2
sum of zeroes = -3 + 2 = -1 = -b/a
product of zeroes = -3×2 =-6 = c/a
k [x^2 -(-1)x +( -6)]
k [x^2 + x - 6] k=1
1[x^2 + x - 6]
x^2 + x - 6
quadratic polynomial = x^2 + x - 6
sum of zeroes = -3 + 2 = -1 = -b/a
product of zeroes = -3×2 =-6 = c/a
k [x^2 -(-1)x +( -6)]
k [x^2 + x - 6] k=1
1[x^2 + x - 6]
x^2 + x - 6
quadratic polynomial = x^2 + x - 6
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