Find the quadratic polynomial whose zeroes are -4 and 3 and verify the relationship between the zeroes and the coefficients.
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Answered by
139
Let Alpha = -4 and Beta = 3.
Sum of zeroes = Alpha + Beta = -4 + 3 = -1
And,
Product of zeroes = Alpha × Beta = -4 × 3 = -12.
Therefore,
Required quadratic polynomial = X² - ( Sum of zeroes)X + Product of zeroes
=> X² - ( -1 ) X + ( -12 )
=> X² + X - 12.
_____________________________
P ( X ) = X² + X - 12
Here,
A = Coefficient of X² = 1
B = Coefficient of X = 1
And,
C = Constant term = -12
Relationship between the zeroes and Coefficients.
Sum of zeroes = Alpha + Beta = -4 + 3 = -1/1 = - ( Coefficient of X ) / ( Coefficient of X²).
And,
Product of zeroes = Alpha × Beta = -4 × 3 = -12/1 = Constant term / Coefficient of X².
Sum of zeroes = Alpha + Beta = -4 + 3 = -1
And,
Product of zeroes = Alpha × Beta = -4 × 3 = -12.
Therefore,
Required quadratic polynomial = X² - ( Sum of zeroes)X + Product of zeroes
=> X² - ( -1 ) X + ( -12 )
=> X² + X - 12.
_____________________________
P ( X ) = X² + X - 12
Here,
A = Coefficient of X² = 1
B = Coefficient of X = 1
And,
C = Constant term = -12
Relationship between the zeroes and Coefficients.
Sum of zeroes = Alpha + Beta = -4 + 3 = -1/1 = - ( Coefficient of X ) / ( Coefficient of X²).
And,
Product of zeroes = Alpha × Beta = -4 × 3 = -12/1 = Constant term / Coefficient of X².
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