Find the quadratic polynomial whose zeroes are 5/2 and -5/2
Answers
Answered by
1
If the zeroes are 5/2 and -5/2, then the factors are x-5/2 and x+5/2.
so, the equation is
=(x-5/2)(x+5/2)
=x^2-5/2x+5/2x-25/4
=x^2-(25/4)
so, the equation is
=(x-5/2)(x+5/2)
=x^2-5/2x+5/2x-25/4
=x^2-(25/4)
Answered by
0
Sum of zeroes = 5+2√3 + 5-2√3
= 5 + 5
= 10
product of zeroes = (5+2√3) (5-2√3)
= (5)² - (2√3)²
= 25 - 4×3
= 25-12
= 13
Quadratic polynomial =
{x }^{2} - {sum of zeroes} + {product of zeroes}x
2
−sum of zeroes+product of zeroes
x² - 10 + 13 is the required polynomial
I Hope this help you
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