Question

Find the quadratic polynomial, whose zeroes are 5 and -8.

Answer 1

Step-by-step explanation:

Required polynomial is given as:

${x}^{2} - (sum \: of \: zeros)x + product \: of \: zeros \\ = {x}^{2} - \{5 + ( - 8) \}x + 5( - 8) \\ = {x}^{2} - (5 - 8)x - 40 \\ = {x}^{2} - ( - 3)x - 40 \\ = {x}^{2} + 3x - 40$

Answer 2

Answer:

$x {}^{2} + 3x - 40$

Step-by-step explanation:

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