Find the quadratic polynomial whose zeroes are 7± √5
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Answered by
151
hi friend,
given zeros of the quadratic polynomial are 7+√5 and 7-√5
→sum of zeros =7+√5+7-√5
=14
→product of zeros =(7+√5)(7-√5)=49-5=44
so, required polynomial is x²-(sum of zeros) x+product of zeros
→x²-14x+44
I hope this will help u ;)
given zeros of the quadratic polynomial are 7+√5 and 7-√5
→sum of zeros =7+√5+7-√5
=14
→product of zeros =(7+√5)(7-√5)=49-5=44
so, required polynomial is x²-(sum of zeros) x+product of zeros
→x²-14x+44
I hope this will help u ;)
malusanthosh10:
Very very thanks
Answered by
37
Sum of zeros =7+√5+7-√5 =14
Product of zeros =(7+√5)(7-√5)=49-5=44
Hence,the required polynomial = x2 - (sum of zeros) x + product of zeros
= x2 -14x + 44
Product of zeros =(7+√5)(7-√5)=49-5=44
Hence,the required polynomial = x2 - (sum of zeros) x + product of zeros
= x2 -14x + 44
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