Question

Find the quadratic polynomial whose zeroes are-8/3 and 4/3

Answer 1

Answer:

x² + 4x - 8 is the required Quadratic polynomial

Step-by-step explanation:

General form of a Quadratic polynomial = x² - (α+β)x +αβ, where α and β are the zeros

Here, α = -8/3 and β = 4/3

Substituting the values, we get,

x² + 4/3x - 24/9

⇒ 3 (x² + 4x - 8)