Question

find the quadratic polynomial whose zeroes are least perfect square and first odd prime​

Answer 1

Least perfect square = 4

First odd prime = 3

So the zeros of the required polynomial are 4 & 3.

We know that,

x² - ( sum of the zeros) x + (product of the zeros)

=> x² - (4+3)x + (4×3)

So, the required polynomial is x²- 7x + 12.

Hope it helps.

Answer 2

Answer:

Last perfect square = 4

First odd prime = 3

So, the zero of the required polynomial are 4 & 3

We know that,

x² - ( sum of the zeros) × + ( product of the zeros)

x² - (4 + 3 )x + (4 × 3)

So, the required polynomial is x² - 7x + 12

Step-by-step explanation:

hope it helps you..