Find the quadratic polynomial whose zeroes are reciprocal of the zeroes of 6²− 3.
Answers
Step-by-step explanation:
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Step-by-step explanation:
Let 6x2 - 7x-3 be p(x) =0
so,6x2 - 7x-3 =0
6x2 - (9-2) x -3
6x2 - 9x + 2x -3
(6x2 - 9x)(2x-3)
3x(2x-3) +1 (2x-3)
(3x +1) (2x -3) = 0
⇒ 3x +1 = 0
⇒ 2x -3 = 0
⇒ x =3/2
⇒ x = - 1/3
sum of zeroes = -1/3 + 3/2 =7/6 = -b/a
product of zeroes =- 1/3 * 3/2 = - 3/6 or -1/2 = c/a