Question

find the quadratic polynomial whose zeroes are squares of the zeroes of the polynomial 3x^2+6x-9​

Answer 1

Answer:

Step-by-step explanation:

Find the zeroes of the given plnl

3x^2+6x-9=0 Sum=6. Product=(-18)9&-3

3x^2-3x+9x-9=0

3x(x-1)+9(x-1)=0

(3x+9)(x-1)=0

3x+9=0. x-1=0

x=-3. x=1

Zeroes of the given plnl is -3&1

Squares of the zeroes= 9&1

Sum= 9+1=10

Product=9*1=9

Therefore the required plnl is x^2-10x+9