Question

Find the quadratic polynomial whose zeroes are the elements of
{ x: XEN, 3<x< 6}​

Answer 1

Answer:

Only natural numbers your set contains are

4 and 5 .

So all we need to write is quadratic whose root are 4 and 5

${x}^{2} - (4 + 5)x + 4 \times 5 \\ = {x}^{2} - 9x + 20$

Answer 2

x² - 9x + 20 is  quadratic polynomial whose zeros are elements of set  { x: X∈N, 3<x< 6}​

Step-by-step explanation:

{ x: X∈N, 3<x< 6}​

=> x = 4   & x = 5

Zeroes are 4  & 5

Quadratic equation

= (x - 4)(x - 5)

= x² - 4x - 5x + 20

= x² - 9x + 20

x² - 9x + 20 is  quadratic polynomial whose zeros are elements of set  { x: X∈N, 3<x< 6}​

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