find the quadratic polynomial whose zeros are 1/2+2root 3and 1/2-2root3
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hey your answer is here;;;;;;;;
by using formula,,
x^2-(a+b)+ab
here,,
a=1/2+2√3
b=1/2-2√3
then a+b=1/2+2√3 + 1/2-2√3. = 1
ab=(1/2+2√3)(1/2-2√3)=13/4
again,,
x^2-(a+b)x+ab
x^2-(1)x+13/4
x^2-x+13/4
4x^2-4x+13 answer......
by using formula,,
x^2-(a+b)+ab
here,,
a=1/2+2√3
b=1/2-2√3
then a+b=1/2+2√3 + 1/2-2√3. = 1
ab=(1/2+2√3)(1/2-2√3)=13/4
again,,
x^2-(a+b)x+ab
x^2-(1)x+13/4
x^2-x+13/4
4x^2-4x+13 answer......
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