Question

Find the quadratic polynomial whose zeros are 1+2√3 and 1-2√3

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Step-by-step explanation:

zeroes are 1+2√3 and 1-2√3

so it's two factors are x-(1+2√3) and x-(1-2√3)

so polynomial is [x-(1+2√3)]*[x-(1-2√3)]

=x^2-(1+2√3)x-(1-2√3)x+(1+2√3)*(1-2√3)

=x^2-(1+2√3+1-2√3)x+(1^2-2√3^2)

=x^2-2x+(1-12)

=x^2-2x-11