Question

find the quadratic polynomial whose zeros are 1/√2 and 1/√2​

Answer 1

Answer:

k/2(2x²-2√2x+1)

Step-by-step explanation:

Hope it helped you.

Answer 2

Answer:

$2 {x}^{2} - \sqrt{2} x + 1 = 0.$

Step-by-step explanation:

$sum = \frac{2}{ \sqrt{2} } = \sqrt{2} \\ \\ product = \frac{1}{2} \\ \\ {x}^{2} - \sqrt{2} x + \frac{1}{2} = 0 \\ \\ 2 {x}^{2} - 2 \sqrt{2} x + 1 = 0.$