Find the quadratic polynomial whose zeros are 1/3 and -1
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Answer:
Step-by-step explanation:
Let the zeroes of the quadratic polynomial be α=1,β=−3
Then, α+β=1+(−3)=−2
αβ=1×(−3)=−3
Sum of zeroes =α+β=−2
Product of zeroes =αβ=−3
Then, the quadratic polynomial =x
2
−( sum of zeroes )x+ product of zeroes =x
2
−(−2)x+(−3)=x
2
+2x−3
Verification:
Sum of zeroes =α+β=1+(−3)=−2 or
=−
Coefficient of x
2
Coefficient of x
=−
1
(2)
=−2
Product of zeroes =αβ=(1)(−3)=−3 or
=
Coefficient of x
2
Constant term
=
1
−3
=−3
So, the relationship between the zeroes and the coefficients is verified.
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