Question

find the quadratic polynomial whose zeros are:-(1)3 and -5 (2) 2/3 and 3/2 (3)5/2 and -5/2 (4) 2√3 and √3/2​

Answer 1

Step-by-step explanation:

1. alpa= 3 and beta= -5

x square - (alpa+ beta)x +alpa(beta)

x square - (3+(-5))x + 3(-5)

x square- (3-5)x -15

x square - (-2)x -15

x square + 2x - 15

2. alpa= 2/3 and beta=3/2

. x square- (alpa + beta)x + alpa(beta)

x square- (2/3+3/2)x + 2/3(3/2)

x square- (4+9/6)x + 4(9)

x square - 13/6x+ 13

x square - (alpa+beta)x + alpa(beta) use this formula you will get other two answers

I hope this answer will help you!