Question

find the quadratic polynomial whose zeros are √2,1/3​

Answer 1

As we know that,

alpha+beta= -b/a

√2+1/3= -b/a

3√2+1/3=-b/a---------------(1)

Now,

alpha×beta=c/a

√2×1/3= c/a----------------(2)

From (1) and (2),we get,

a=3

b=-3√2-1

c= √2

Required polynomial= ax^2+bx+c

= 3-3√2-1+√2

= 3-2√2-1

Ans 3-2√2-1

According to me

Is it right?

If not, then give the correct answer

Answer 2

Answer:

Step-by-step explanation:

Given zeroes of quadratic polynomial are √2 and 1/3.

To find that we have to find sum of roots(S.O.R) and product of roots (P.O.R)

S.O.R = √2 + 1/3 =( 3√2+1)/3

P.O.R = √2/3

Quadratic equation is also given through a formula which is x^2 -(S.O.R) x+(P.O.R)

Q.E = x^2-[(3√2+1)/3]x + √2/3

= 3 x^2 -(3√2+1)x + √2