Find the quadratic polynomial whose zeros are 2+√2/5 and 2-√2/5
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Answer:
Step-by-step explanation:
Firstly sum of zeroes = 2+√2/5 + 2-√2/5
=4
Product of zeros = (2+√2/5) (2-√2/5)
= (2)^2 - (√2/5)^2
= 4 - 2/5
= 18/5
For quadratic polynomial
x^2 - Sx + P
Where S is sum of zeroes and P is product of zeroes
So polynomial is
x^2 - 4x + 18/5
Take 5 as lcm
5x^2 - 20x + 18
is the required polynomial
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