Question

find the quadratic polynomial whose zeros are, 2/3 and - 1 /4
verify the relation between Coefficient and the zero of the polynomial

Answer 1

Hey Dear !!!
__________
Here is ur answer


Sum of zeroes ==》 2/3
Product of zeroes ==》 -1/4

by using formula >> x^2 - ( sum)x + (product) =0

x^2 - (2/3)x + (-1/4) = 0
12x^2 - 8x - 3 = 0

Hope its help...dear

Answer 2

Concept Introduction:

The definition of a quadratic as a second-degree polynomial equation demands that at least one squared term must be included. It also goes by the name quadratic equations.

Given, the quadratic polynomial whose zeros are, $2/3$ and $- 1 /4$.

To find, the relation between the coefficient and the zero of the polynomial.

Solution:

Sum of zeroes = $2/3$

Product of zeroes = $-1/4$

by using the formula,

$x^2$ - ( sum)$x$ + (product) =0

$x^2 - (2/3)x + (-1/4) = 0$

$12x^2 - 8x - 3 = 0$

Final Answer:

The final answer is $12x^2 - 8x - 3 = 0$

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