find the quadratic polynomial whose zeros are √2 + 3 and √2 - 3
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Hello!! brother I beg your pardon if my answer is wrong
Please give thanks for trying=-=
Now I coming to ur question
Answer
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
Let
alpha= √2+3 and Bita=√2-3
now
x^2-(alpha+bita)+alpha. bita
=x^2-(√2+3+√2-3)+(√2+3).(√2-3)
=x^2-2√2x+(√2)^2-(3)^2
=x^2-2√2x+2-9
=x^2-2√2x-7
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>><
Please give thanks for trying=-=
Now I coming to ur question
Answer
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>
Let
alpha= √2+3 and Bita=√2-3
now
x^2-(alpha+bita)+alpha. bita
=x^2-(√2+3+√2-3)+(√2+3).(√2-3)
=x^2-2√2x+(√2)^2-(3)^2
=x^2-2√2x+2-9
=x^2-2√2x-7
>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>><
Anonymous:
wright answer
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