Question

find the quadratic polynomial whose zeros are 2/3 and -7/6​

Answer 1

Step-by-step explanation:

Given,

let one zero be alpha = 2/3

let another zero be beta = -7/3

So,

sum of zeores = aplha + beta = 2/3-7/3 = 2-7/3

= -5/3

product of zeroes = alpha x beta = 2/3 x -7/3

= -14/9

So,

x^2 - (alpha + beta) x + alpha x beta

x^2 - (-5/3)x -14/9

9x^2 + 15 x -14 = 0