Question

Find the quadratic polynomial whose zeros are 2 and - 6. Please no scam​

Answer 1

Let ∝ = 2 and β = -6 Sum of the zeroes = (∝ + β) = 2 – 6 = -4 Product of the zeroes, = 2(-6) = -12 Required quadratic polynomial is x2 – (∝+β)x + ∝β = x2 – (-4)x – 12 = x2 + 4x – 12 And, Sum of the zeroes = – 4 = -4/1 = (-Coefficient of x)/(Cofficient of x2) Product of zeroes = -12 = -12/1 =

Answer 2

Answer:

Step-by-step explanation:

Hi friend ,

Sum of zeros = 2+(-6) = 2-6 = -4

Product of zeros = 2×-6 = -12

Quadratic polynomial:

x^2-( sum of zeros )x + Product of zeros

x^2 -(-4)x +(-12)

x^2 +4x-12

Relation between the coefficient and the zeros of the polynomial:

• Sum of zeros = -b/a

= -4/1

= -4

= -4

• Product of zeros = c/a

= -12/1

= -12

= -12

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