Find the quadratic polynomial whose zeros are 2 and -6. Verify the relation between the coefficients and the zeros of the polynomial.
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Step-by-step explanation:
Here, one zero = 2 ; 2nd zero = - 6
So, polynomial = (x-2)(x-(-6))
=(x-2)(x+6)
= x²+4x-12
Hence, Quadratic polynomial whose zeros are 2 and -6 is x²-4x-12.
Verify,,
Sum of zero = -b/c
2+(-6)= -(4)/1
-4 = - 4
Or,
product of zero = c/a
2×(-6)= -12/1
- 12 = - 12
So, hence proof.
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