find the quadratic polynomial whose zeros are 2 upon 3 and minus 1 upon 4 verify the relation between the coefficient and the zeros of the polynomial
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Answered by
18
Answer:
Step-by-step explanation:
Given,
α=2/3 and β=-1/4
Sum = 2/3-1/4=(8-3)/12=5/12=-b/a
Product =
2/3*-1/4=-1/6=c/a=-1/6*2/2=-2/12
=> a = 12 , b = -5 , c = -2
General form of quadratic equation :-
ax^2+bx+c=0
So, required quadratic equation :-
12x^2-5x-2=0
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Answered by
7
α+β = 2/3-1/4 = -b/a
= 2 x 4 - 1 x 3
------------------
12
= 8-3/12
= 5/12
αβ = 2/3 * -1/4 =c/a
= -2/12
=k [X² - (α+β)X + αβ]
=k[ X² - (5/12)X + (-2/12)
= k[12 X² -5 X -2]
--------------------
12
if k = 12,
then quadratic equation is :
12X² - 5X -2....
hope it help you
= 2 x 4 - 1 x 3
------------------
12
= 8-3/12
= 5/12
αβ = 2/3 * -1/4 =c/a
= -2/12
=k [X² - (α+β)X + αβ]
=k[ X² - (5/12)X + (-2/12)
= k[12 X² -5 X -2]
--------------------
12
if k = 12,
then quadratic equation is :
12X² - 5X -2....
hope it help you
vivo1726:
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