Math, asked by shashank2662, 1 year ago

find the quadratic polynomial whose zeros are 2 upon 3 and minus 1 upon 4 verify the relation between the coefficient and the zeros of the polynomial​

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Answers

Answered by wwwHarshSable
18

Answer:

Step-by-step explanation:

Given,

α=2/3 and β=-1/4

Sum = 2/3-1/4=(8-3)/12=5/12=-b/a

Product =

2/3*-1/4=-1/6=c/a=-1/6*2/2=-2/12

=> a = 12 , b = -5 , c = -2

General form of quadratic equation :-

ax^2+bx+c=0

So, required quadratic equation :-

12x^2-5x-2=0

Pl mark it the brainliest answer if it helps you to get satisfaction of knowledge and experience it....

Answered by vivo1726
7
α+β = 2/3-1/4 = -b/a

= 2 x 4 - 1 x 3
------------------
12

= 8-3/12

= 5/12

αβ = 2/3 * -1/4 =c/a

= -2/12

=k [X² - (α+β)X + αβ]

=k[ X² - (5/12)X + (-2/12)

= k[12 X² -5 X -2]
--------------------
12

if k = 12,

then quadratic equation is :

12X² - 5X -2....

hope it help you

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