Question

find the quadratic polynomial whose zeros are 3-√3/5 and 3+√3/5​

Answer 1

3-√3/5 and 3+√3/5 are the zeroes of the quadratic polynomial.

Let α=3-√3/5 and β=3+√3/5

Sum of zeroes =α+β

=3-√3/5+3+√3/5

=6

Product of zeroes =αβ

=(3-√3/5)(3+√3/5)

=3(3+√3/5)-√3/5(3+√3/5)

=9+3√3/5-3√3/5-3/25

=9-3/5

=45-3/5

=42/5

The quadratic polynomial which has two zeroes is in the form

x²-(α+β)x+αβ

=x²-(6)x+(42/5)

=x²-6x+42/5

Hope it helps

Answer:

25x^2+30x-6

Step-by-step explanation:

the zeros are-

--> 3-/5

--> 3+/5

product of zeroes:-

(3-+3+)/5 = 6/5

sum of zeros:-

(3-)/5 * (3+)/5 = 9-3/25=6/25

now,

x^2-(  )x+(  )=0

x^2/1-6/25+6/5*x=0

(25x^2+30x-6)/25=0

25(25x^2+30x-6)/25=0

25x^2+30x-6=0

hence, it is the quadratic polynomial.

Answer 2

Answer:

Step-by-step explanation: