find the quadratic polynomial whose zeros are 3+√7,3-√7
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I hope this answer is correct
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Hiii friend,
Alpha = 3+✓7 and Beta = 3-✓7
Sum of zeros = (Alpha + Beta) = (3+✓7+3-✓7) = 6
Product of zeros = (Alpha × Beta) = (3+✓7)(3-✓7) = (3)² - (✓7)² = 9-7 = 2.
Therefore,
REQUIRED POLYNOMIAL = X²-(Alpha + Beta)X + Alpah × Beta
=> X²-6X+2
HOPE IT WILL HELP YOU..... :-)
Alpha = 3+✓7 and Beta = 3-✓7
Sum of zeros = (Alpha + Beta) = (3+✓7+3-✓7) = 6
Product of zeros = (Alpha × Beta) = (3+✓7)(3-✓7) = (3)² - (✓7)² = 9-7 = 2.
Therefore,
REQUIRED POLYNOMIAL = X²-(Alpha + Beta)X + Alpah × Beta
=> X²-6X+2
HOPE IT WILL HELP YOU..... :-)
Saumya9139:
u r real genius
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