find the quadratic polynomial whose zeros are -3 and 2
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form of a quadratic equation in terms of zeroes is :
K[ x² - ( α+β)x+αβ]
let α= (-3) and β=2
⇒ K[x²-((-3)+2)x+ ( -3)(2)]
⇒K [ x² - (-1)x +(-6)]
⇒K [ x² + x-6]
let K=1,
∴ required polynomial is x²+x-6
divsaraswat1p7owmi:
its not right
it is the correct answer.
no
silly mistake in multiplication
-3*2=-6 not 6
now you got it
:-D Shame bhai
I have written -6 bhai
dhyan se dekh
Ae bhai zara dekh ke chalo agge bhi par piche bhi upar hi nhi niche bhi ae bhai
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