Question

find the quadratic polynomial whose zeros are - 4 and 3 and verify the relationship between zeros and coefficient​

Answer 1

Answer:

i am giving it step by step

Step-by-step explanation:

zeroes are -4 and 3

now sum of zeroes is -1

and product is -12

f(x)=k{$x^{2}$-(sum of zeroes)x+(product of zeroes)}

f(X)=k{$x^{2}$-(-1)x+(-12)

f(x)=k{$x^{2}$+x-12}

you can take k=1 for simplicity

so.....

f(x)=$x^{2}$+x-12

now sum of zeros=-coefficients ofx/coeefificents of $x^{2}$

and product=constant  /coefficient of $x^{2}$

now you can verify it yourself

hope you understand

Answer 2

Answer:

x²+1x-12=0

Step-by-step explanation:

see the attachment done with the solution