Question

find the quadratic polynomial whose zeros are 5 and 8​

Answer 1

Answer:

Given, x = 5 &x = -8

Therefore, (x-5) = 0 & (x+8)= 0

Multiplying both terms

(x-5) (x+8)

x² + 8x - 5x - 40

x² + 3x -40

Hence, it is required quadratic polynomial.

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Answer 2

Answer:

x²-13x+40

Step-by-step explanation:

$\alpha = 5$

$\beta = 8$

$\alpha + \beta = 5 + 8 = 13$

$\alpha \beta = 5(8) = 40$

Substitute in the formula

$x^{2} - ( \alpha + \beta )x + \alpha \beta$

x²-13x+40