find the quadratic polynomial whose zeros are 6+√3/3 and 6-√3/3
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Answer:
the quadratic equation will be 3 x square minus 36 X + 107
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Step-by-step explanation:
The zeros of the polynomial are given as 53−3 and 63+3. So,
α=53−3 and β=63+3
The quadratic equation is of the form,
x2−(α+β)x+αβ=0
x2−(53−3+63+3)x+(53−3)(63+3)=0
x2−(306(3−3)+5(3+3))x+
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