Math, asked by samangupta, 7 months ago

Find the quadratic polynomial whose zeros are (7-9/2) and (7+972) respectively​

Answers

Answered by ToxicEgo
0

Answer:

Let alpha=7-9/2 and beta =(7+972) =979

therefore, alpha=14-9/2=5/2

Since, alpha+beta=5/2+979

=1963/2

alpha×beta=5/2×979=4895/2

Therefore, Required quadratic equation is

x²-(alpha+beta) x+alpha beta

→x²-1963/2+4895/2

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