Find the quadratic polynomial whose zeros are -8 and 2 verify the relation between the co eeficient and the zeros of the polynomial now solution
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A quadratic polynomial is given by :-
k(x²-(sum of zeroes)x + (product of zeroes))
k(x² -(-8+2)x + (-8*2))
k (x² +6 x -16)
Here k=1
So quadratic polynomial is x^2 +6x -16
Sum of zeroes = -b/a = -6/1 = -6
Product of zeroes = c/a = 16
k(x²-(sum of zeroes)x + (product of zeroes))
k(x² -(-8+2)x + (-8*2))
k (x² +6 x -16)
Here k=1
So quadratic polynomial is x^2 +6x -16
Sum of zeroes = -b/a = -6/1 = -6
Product of zeroes = c/a = 16
Anonymous:
srry i clicked so many tyms that's y
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no idea sorry but i dont know this ans.
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