Find the quadratic polynomial whose zeros are (a) 3 , 5
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Answer:
k [x^2 - 8x + 15]
Step-by-step explanation:
Sum of zeroes = 3 + 5 = 8
Product of zeroes = 3 * 5 = 15
Equation = k [x^2 - (alpha +beta)x + (alpha * beta)]
= k [x^2 - 8x + 15]
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sorry i don't no this answer
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