Math, asked by Smriti404, 10 months ago

Find the quadratic polynomial whose zeros are (a) 3 , 5

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Answered by Anonymous
0

Answer:

k [x^2 - 8x + 15]  

Step-by-step explanation:

Sum of zeroes = 3 + 5 = 8

Product of zeroes = 3 * 5 = 15

Equation = k [x^2 - (alpha +beta)x + (alpha * beta)]

               = k [x^2 - 8x + 15]  

         

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Answered by bhaktigade2007
0

sorry i don't no this answer

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