Math, asked by sonykalra96, 4 months ago

Find the quadratic polynomial whose zeros are ⅔ and -1/4. Verify the relation

between the coefficients and the zeros of the polynomial.

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Answered by shamsqamarshams
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Answer:

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Shaan2081

15.05.2019

Math

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answered • expert verified

Find the quadratic polynomial whose zeroes are 2 and _6 respectively, verify the relation between the coefficient and zeroes of the polynomials

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KDPatak

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Answer:

Given:

the quadratic polynomial whose zeroes are 2 and _6

To find :

The polynomial and verify the relationship.

Solving Question:

we are given the zeros of the polynomial, hence we can find the polynomial through these equations.

If α and β are the zeros

α + β = -b/a

α * β = c/a

Solution:

α + β = 2 + (-6)

= 2-6

= -4 = -b/a

⇒ a = 1 ; b = 4

α * β = 2 *(-6)

= -12 = c/a

⇒ c = -12

Standard form : ax² + (α + β )x + α*β

the equation becomes k(x² + 4x -12 ) , where 'k' is a constant.

Relationship ;

α + β = -4 = -b/a

α * β = -12 = c/a

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ankitasharma

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Heya see the pic below for solution. Hope it helps you. Kindly mark it brainliest.

The verification is indeed in the process.

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Answered by ag0008699
0

Answer:

zeros are 2/3 and -1/4.

=(x-2/3)(x+1/4)

=x²+x/4-2x/3-2/12

=x²+3x-8x/12-2/12

=x²-5x/12-2/12

=12x²-5x-2/12

=12x²-5x-2

verification

α+β=-b/a

2/3+(-1/4)=-(-5)/12

8-3/12=5/12

5/12=5/12

lhs=rhs

αβ = c/a

2/3×(-1/4)=-2/12

-2/12=-2/12

lhs=rhs

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